Question

Factorize please help​

Answer 1

Step-by-step explanation:

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Answer 2

$\Large{\underbrace{\sf{\red{Required\:Solution:}}}}$

(√5 + √3)²

Sol'n.

$\implies{\sf{ (\sqrt{5} + \sqrt{3})^{2}}}$

• Identity used - (α+b)² = α²+2αb+b²

$\implies{\sf{ (\sqrt{5})^{2} + 2\times \sqrt{5}\times \sqrt{3} + (\sqrt{3})^{2}}}$

$\implies{\sf{ 5 + 2\sqrt{15} + 3}}$

$\large\implies{\boxed{\sf{\red{ 2\sqrt{15} +8}}}}$

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Algebrαic identity - An αlgebrαic identity is αn equαlity thαt holds for αny vαlues of its vαriαbles.

e.g.,

• (a+b)² = a² + 2ab + b²
• (a-b)² = a² - 2ab + b²
• a²-b² = (a-b)(a+b)
• a²+b² = (a+b)² - 2ab
• (x+a)(x+b) = x² + (a+b)x + ab
• (a+b)³ = a³ + b³ + 3ab(a+b)
• (a-b)³ = a³ - b³ - 3ab(a-b)
• a³+b³ = (a+b)³-3ab(a+b)

⠀⠀⠀⠀⠀⠀⠀= (a+b) (a²- ab + b²)

• a³-b³ = (a-b)³+3ab(a-b)

⠀⠀⠀⠀⠀⠀⠀= (a-b) (a² + ab + b²)

• (a+b+c)² = a² + b² + c² + 2ab + 2bc + 2ca
• (a-b-c)² = a² + b² + c² - 2ab + 2bc - 2ca
• (a-b+c)² = a² + b² + c² - 2ab - 2bc + 2ca

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