Question

Factorize...
Plz do it fast​

Answer 1

hola

take lcm 5 and 5 is 5

2x^2 - 5x - 3 / 5

2x^2 - 6x + x - 3/ 5

2x (x - 3 ) +1 ( x- 3) / 5

(x-3) (2x +1 ) /5

$♥SHARMA JI HERE ♥</p><p></p><p></p><p></p><p></p><p>[] HELLO DEAR []</p><p></p><p><svg class= "heart" viewBox= "-2 -2 98.6 90.81"></p><p></p><p><title>Corazon</title></p><p></p><p><path stroke= "firebrick" stroke-width= "3" d= "M86.81,8.15a27.79,27.79,0,0,1,0,39.33L47.48,86.81,8.15,47.48A27.81,27.81,0,0,1,47.48,8.15,27.79,27.79,0,0,1,86.81,8.15Z"/></p><p></p><p></svg></p><p></p><p><style></p><p></p><p>body {</p><p></p><p>display: grid;</p><p></p><p>min-height: 100vh;</p><p></p><p>justify-content: center;</p><p></p><p>align-content: center;</p><p></p><p>background: repeating-linear-gradient(circle, white, pink, red);</p><p></p><p>background: repeating-radial-gradient(circle, white, pink, orange);</p><p></p><p>}</p><p></p><p>@keyframes heart-path {</p><p></p><p>99% {</p><p></p><p>stroke-dashoffset: 0;</p><p></p><p>fill: none;</p><p></p><p>}</p><p></p><p>100% {</p><p></p><p>fill: firebrick;</p><p></p><p>}</p><p></p><p>}</p><p></style>$

mark me and follow me

Answer 2

Question :-

Correct Question should be

$\frac{2}{5} x {}^{2} - x + \frac{3}{5} = 0$

Solution :-

$\frac{2}{5} {x}^{2} - x + \frac{3}{5} = 0$

Now multiply by 5 in every term

$5 \times \frac{2}{5} {x}^{2} - 5x + 5 \times \frac{3}{5} = 5 \times 0 \\ \\ 2 {x}^{2} - 5x + 3 = 0$

Now Factorise by splitting middle term

$2 {x}^{2} - 2x - 3x + 3 = 0 \\ \\ 2x(x - 1) - 3(x - 1) = 0 \\ \\ (x - 1)(2x - 3) = 0$

Now split it into possible cases

$(x - 1) = 0 \\ \\ (2x - 3) = 0$

Hence,

$x_1 = 1 \\ \\ x_2 =( \frac{3}{2} )$

Extra information :-

• A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.