factorize sin4A-sin2A
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|| sin4A - sin2A ||
= sin 2( 2A ) - sin 2A
= 2 sin2 A cos 2 A - sin 2 A
= sin 2 A ( 2 cos2 A - 1 )
= sin 2 A ( 2 ( cos^2 A - sin^2 A ) - 1 )
= sin2A { 2(cosA - sinA ) (cosA + sinA) -1}
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|| : hope helps : ||
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= sin 2( 2A ) - sin 2A
= 2 sin2 A cos 2 A - sin 2 A
= sin 2 A ( 2 cos2 A - 1 )
= sin 2 A ( 2 ( cos^2 A - sin^2 A ) - 1 )
= sin2A { 2(cosA - sinA ) (cosA + sinA) -1}
_______________________________
|| : hope helps : ||
_______________________________
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Answer:
Step-by-step explanation:
Sin4a-sin2a=2sin(4a+2a) /2×cos(4a-2a)/2=2sin3a×cosa
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