Question

◆ Factorize :-
$1) \: 36 {a}^{2} - 25$
$2) \: {x}^{2} + 12x + 36$
$3) \: {y}^{2} - 7y + 12$
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Answer 1

Answer:

hope it helps you!!!!!!

Answer 2

Question :-

Factorize :-

$\sf1) \: 36 {a}^{2} - 25$

$\sf2) \: {x}^{2} + 12x + 36$

$\sf3) \: {y}^{2} - 7y + 12$

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Solution :-

$\sf1.) \: \: \sf36 {a}^{2} - 25$

$: \implies \sf{(6a)}^{2} - {(5)}^{2}$

$: \implies \sf(6a + 5)(6a - 5) \\ \boxed{\sf{using \: the \: property : {a}^{2} - {b}^{2} = (a + b)(a - b)}}$

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$\sf2.) \: \: \sf{x}^{2} + 122 + 36$

$: \implies \sf{x}^{2} + 6x + 6x + 36$

$: \implies \sf x(x + 6) + 6(x + 6)$

$: \implies \sf (x + 6)(x + 6)$

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$\sf3.) \: \: \sf { y}^{2} - 7y + 12$

$: \implies \sf {y}^{2} - 4y - 3y + 12$

$: \implies \sf y(y - 4) - 3(y - 4)$

$: \implies \sf(y - 4)(y - 3)$

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Final Answers :-

$\sf1.) \: \: \sf(6a + 5)(6a - 5)$

$\sf2.) \: \: \sf(x + 6)(x + 6)$

$\sf3.) \: \: \sf(y - 4)(y - 3)$

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