Math, asked by ridhamshah30, 2 days ago

Factorize :-

27a {}^{2}  + 72ab + 48 {b}^{2}


mddilshad11ab: 3{9a²+24ab+16b²}
mddilshad11ab: 3{(3a)²+(4b)²+2.3a.4b} => 3(3a+4b)(3a+4b)

Answers

Answered by kushalsaini248
3

Hope ,it helpful for you

Attachments:
Answered by LaCheems
9

{\huge{\red{\boxed{A}{\orange{\boxed{N}{\green{\boxed{S}{\blue{\boxed{W}{\gray{\boxed{E}{\purple{\boxed{R→}}}}}}}}}}}}}}

27a {}^{2} + 72ab + 48 {b}^{2} \\  \\ we \:  \: see \:  \: that \:  \: every \:  \: no. \:   \\ \: here \:  \: is \:  \: divisble \:  \: by \:  \: 3. \\  \\ so... \\  \\  = 3(27 {a}^{2} ) + 3(72ab) + 3(48 {b}^{2}) \\  \\  = 3(9 {a}^{2} ) + 3(24b) + 3(16 {b}^{2} ) \\  \\  \\ take \:  \: 3 \:  \: common \:  \: \\  from \:  \: each. \\  \\ =  {\boxed{ 3(9 {a}^{2} + 24b + 16 {b}^{2})}}

HOPE IT HELPS

:)

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