Question

Factorize
$2x {}^{2} - 3x - 5$
​

Answer 1

Answer:

2x²-3x-5

= 2x²-5x+2x-5 (Split the middle term)

=x(2x-5)+1(2x-5)

=(2x-5)(x+1) or (x+1)(2x-5).

Answer 2

☤ Solution:

$\implies$ 2x² - 3x - 5

:: We have to find that two numbers whose product is 10 and whose addition or substrate is 3 .

So that numbers be 5 and 2.

Product $\implies$ 5 × 2 = 10

Substrate $\implies$ 5 - 2 = 3

$\implies$ 2x² - 3x - 5

$\implies$ 2x² - (5 - 2)x - 5

$\implies$ 2x² - 5x + 2x - 5

$\implies$ x(2x - 5) + 1(2x - 5)

$\implies$ (2x - 5) (x + 1)

Hence,

Factorised !!