Question

factorize
$2x {3 - 9x {2 + 13x - 6}^{?} }^{?}$

Answer 1

hello!

#ur solution
__________

put the Value of X= 1 which is factor of -6

=> 2(1)^3 -9(1)^2 +13*1 -6 = 0

=> 2 -9 +13 -6 =0

=> 15-15 =0

=> 0=0

Now
(x-1) is factor of equation

$2 {x}^{2} (x - 1) - 7x(x - 1) + 6(x - 1) \\ \\ (x - 1)(2x {}^{2} - 7x + 6) \\ \\now \: factorise \\ (x - 1)(2x {}^{2} - 4x - 3x + 6) \\ \\ (x - 1)(2x(x - 2) - 3(x - 2)) \\ \\ (x - 1)(2x - 3)(x - 2) \: ans$


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Answer 2

Step-by-step explanation:

put the Value of X= 1 which is factor of -6

=> 2(1)^3 -9(1)^2 +13*1 -6 = 0

=> 2 -9 +13 -6 =0

=> 15-15 =0

=> 0=0

Now

(x-1) is factor of equation

\begin{gathered}2 {x}^{2} (x - 1) - 7x(x - 1) + 6(x - 1) \\ \\ (x - 1)(2x {}^{2} - 7x + 6) \\ \\now \: factorise \\ (x - 1)(2x {}^{2} - 4x - 3x + 6) \\ \\ (x - 1)(2x(x - 2) - 3(x - 2)) \\ \\ (x - 1)(2x - 3)(x - 2) \: ans\end{gathered}

2x

2

(x−1)−7x(x−1)+6(x−1)

(x−1)(2x

2

−7x+6)

nowfactorise

(x−1)(2x

2

−4x−3x+6)

(x−1)(2x(x−2)−3(x−2))

(x−1)(2x−3)(x−2)ans

hope this helps you!!