Question

factorize
${a}^{2} - {b}^{2} \: - 4ac + 4bc$

Answer 1

● Factorisation ●

a² - b² - 4ac + 4bc

= (a + b)(a - b) - 4c(a + b)

= (a + b) [ (a - b) - 4c]

= (a + b)(a - b - 4c)