Question

factorize

$\sqrt{2x {}^{2} } + 3x + \sqrt{2}$
Pls solve it fast ​

Answer 1

Answer:

x = -√2, x = -1/√2

Step-by-step explanation:

Factorize √2x² + 3x + √2

==> √2x² + 2x + x + √2

==> √2x(x + √2) + 1(x + √2)

==> (√2x + 1)(x + √2)

Zeroes are,

x = -√2, x = -1/√2

#BeBrainly

Answer 2

Step-by-step explanation:

$\sqrt{2} {x}^{2} + 3x + \sqrt{2} \\ = \sqrt{2} {x}^{2} + 2x + x + \sqrt{2} \\ = \sqrt{2} \: x (x + \sqrt{2} ) + 1(x + \sqrt{2} ) \\ = (x + \sqrt{2} )(x \sqrt{2} + 1)$

_______&&&&&&&________

//HOPE THIS WILL HELPED YOU//

//PLEASE MARK IT AS BRAINLIEST//

#BAL. #ANSWERWITHQUALITY