Factorize
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Answered by
4
Hey dear!
Here is yr answer.......
=> x² - 1
=> x² - 1²
[ x²-y² = (x+y) (x-y) ]
x = x , y = 1
=> (x+1) (x-1)
Hope it hlpz..
Here is yr answer.......
=> x² - 1
=> x² - 1²
[ x²-y² = (x+y) (x-y) ]
x = x , y = 1
=> (x+1) (x-1)
Hope it hlpz..
Answered by
4
Hey mate!
Here's your answer!!
________________
Given: x² - 1
➡ This above mentioned equation is the difference of two squares.
a² - b² = (a - b) (a+b)
So, in general form..... x² - 1 can be....
x² - 1 = (x - 1)(x +1)
________________
✌ ✌ ✌
✪ Be Brainly ✪
Here's your answer!!
________________
Given: x² - 1
➡ This above mentioned equation is the difference of two squares.
a² - b² = (a - b) (a+b)
So, in general form..... x² - 1 can be....
x² - 1 = (x - 1)(x +1)
________________
✌ ✌ ✌
✪ Be Brainly ✪
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