Question

factorize:
$x ^{3} - 23x ^{2} + 142x - 120$

Answer 1

(X - 12) (x - 10 ) ( x- 1)


Best of luck and try hard

Answer 2

$\textbf{ Hello Mate! }$

p(x) = x^3 - 23x^2 + 142x - 120

Keeping x once 0 and 1 we get

p(0) = 0^3 - 23(0)^2 + 142(0) - 120
= - 120

Hence, 0 can't be value of x

p(1) = 1^3 - 23(1) + 142(1) - 120
= 1 - 23 + 142 - 120
= 143 - 143 = 0

Hence, value of x = 1
Thus, 1 factor of p(x) = ( x - 1 )

Next, please refer to attatchment.

$\boxed{ Factors:(x-1)(x-12)(x-10) }$

Have great future ahead!