Question

factorize: [tex]x^{3} - x - 2y + 8x^{3}

Answer 1

$\star\:\:\bf\large\underline\blue{Question:-}$

• Factorise ${x}^{3} - x - 2y + 8 {y}^{3}$

$\star\:\:\bf\large\underline\blue{Solution:-}$

${x}^{3} - x - 2y + 8 {y}^{3}$

$= {x}^{3} + 8{y}^{3} - x - 2y$

$= {(x)}^{3} + {(2y)}^{3} - 1(x + 2y)$

$= (x + 2y)( {x}^{2} - 2xy + 4 {y}^{2} ) - 1(x + 2y)$

$= (x + 2y)( {x}^{2} + 4 {y}^{2} - 2xy - 1)$

$\star\:\:\bf\large\underline\blue{Answer:-}$

• $(x + 2y)( {x}^{2} + 4 {y}^{2} - 2xy - 1)$

Answer 2

Answer:

9x^{3} -x -2y is your answer

Step-by-step explanation:

= x^{3} - x - 2y + 8x^{3}

= x^{3} + 8x^{3} - x - 2y

= 9x^{3} -x -2y

9x^{3} -x -2y is your answer

Hope this answer was helpful

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