Question

factorize

${x}^{6} + {64y}^{6}$
​

Answer 1

Answer:

$( {x}^{2} + 4 {y}^{2} )( {x}^{2} - 4 {x}^{2} {y}^{2} + 16 {y}^{6} )$

Step-by-step explanation:

${x}^{6} + {(2y)}^{6} = {( {x}^{2}) }^{3} + {( {4y}^{2}) }^{3} \\ \\ = ( {x}^{2} + 4 {y}^{2} )( {x}^{2} - 4 {x}^{2} {y}^{2} + 16 {y}^{6} )$