Question

Factorize
$x(x + y)^{3} - 3yx^{2} (x + y)$​

Answer 1

$x(x + y)^{3} - 3yx^{2} (x + y)$

$= \blue {x(x + y)} (x+y)^{2} - 3yx\times\blue {x(x + y)}$

$= \blue {x(x + y)} [(x+y)^{2} - 3yx]$

Therefore .,

$\red {x(x + y)^{3} - 3yx^{2} (x + y)}$

$\green {=x(x + y) [(x+y)^{2} - 3yx]}$

•••♪

Answer 2

x(x + y)^{3} - 3yx^{2} (x + y)x(x+y)

3

−3yx

2

(x+y)

= \blue {x(x + y)} (x+y)^{2} - 3yx\times\blue {x(x + y)}=x(x+y)(x+y)

2

−3yx×x(x+y)

= \blue {x(x + y)} [(x+y)^{2} - 3yx]=x(x+y)[(x+y)

2

−3yx]

Therefore .,

\red {x(x + y)^{3} - 3yx^{2} (x + y)}x(x+y)

3

−3yx

2

(x+y)

\green {=x(x + y) [(x+y)^{2} - 3yx]}=x(x+y)[(x+y)

2

−3yx]

•••♪

Thanks!!!