Math, asked by Anonymous, 8 months ago

Factorize
${y}^{2} - y - 6$

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Answered by Anonymous

Step-by-step explanation:

${y}^{2} - y - 6 = {y}^{2} - 3y + 2y - 6 = 0 = > y(y - 3) + 2(y - 3) = > (y + 2)(y - 3) = 0 = > y = 3 \: \: and \: \: y = - 2$

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Answered by Anonymous

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${y}^{2} - y - 6$

${y}^{2} - 3y + 2y - 6$

$y(y - 3) + 2(y - 3)$

$(y - 3)(y + 2)$

hope it helps you.....

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Factorize
${y}^{2} - y - 6$