Math, asked by fatso3, 1 year ago

factorize the difference of two squares: (9+x)^2-(4-x)^2. show your workings​

Answers

Answered by sagarmankoti
1

 {(9 + x)}^{2}  -  {(4 - x)}^{2}  \\  = [(9 + x) + (4 - x)] \times [(9 + x) - (4 - x)] \:  \:   \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \: |  \:  \: because \:  {x}^{2}  -  {y}^{2}  = (x + y)(x - y) \\  = (9 + x + 4 - x)(9 + x - 4 + x) \\  = (13)(5 + 2x) \\  = 65 + 26x


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Answered by nupur90
1

HOPE u like the answer

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fatso3: i dont think it correct
nupur90: yah its not editing
fatso3: ohk. tynks
nupur90: its 26x kk
fatso3: when u multiply 13 by 5 gives 65. then multiply 13 by 2x gives 26x
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