Question

Factorize the equation 2a^7-128a

Answer 1

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Answer 2

2a^7-128a

2a(a^6-64)

2a[(a^3)^2-(8)^2]

A^2-B^2= (A+B)(A-B)

So, 2a(a^3+8)(a^3-8)

2a(a^3+8)(a^3-2^3)

OR

2a(a^3+8)(a-3)(a^2+4+2a)