Question

factorize the expression 2x^2-4x+5

Answer 1

Answer:

$2 {x}^{2} - 4x + 5 = 0 \\ x = \frac{ - {b} \frac{ + }{ - } \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{4 \frac{ + }{ - } \sqrt{16 - 4 \times 2 \times 5} }{4} \\ x = \frac{4 \frac{ + }{ - } 2 \sqrt{4 - 10} }{4} \\ x = \frac{2\frac{ + }{ - } \sqrt{ - 6} }{4}$

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