Question

factorize the expression 2x³-7x²-3x-18

Answer 1

2x³ + 7x² - 3x - 18
put x = -2
we get 
2(-2)³ + 7(-2)²-3(-2)-18
= -16+28+6-18
= 34-34 = 0

Answer 2

Answer:

Step-by-step explanation:

2x³ + 7x² - 3x - 18

put x = -2

we get 

2(-2)³ + 7(-2)²-3(-2)-18

= -16+28+6-18

= 34-34 = 0

hence x = -2 is root of 2x + 7x - 3x - 18

hence

2x³ + 7x² - 3x - 18 = (x+2)(2x²+3x-9)

=(x+2)(2x²+6x-3x-9)

=(x+2){2x(x+3)-3(x+3)}

=2x³+7x²-3x-18 = (x+2) (x-3) (2x-3)