Factorize the expression p^3+27
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Step-by-step explanation:
p3 + 27 = p3 + 33 [a3 + b3 = (a + b)(a2 –ab + b2)] = (p + 3)(p2 – 3p – 9) Therefore, p3 + 27 = (p + 3)(p2 – 3p – 9).Read more on Sarthaks.com - https://www.sarthaks.com/604914/factorize-p-3-27
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Answer:
it will be like this
Step-by-step explanation:
p3 + 27 = p3 + 33 [a3 + b3 = (a + b)(a2 –ab + b2)] = (p + 3)(p2 – 3p – 9) Therefore, p3 + 27 = (p + 3)(p2 – 3p – 9).Read more on Sarthaks.com - https://www.sarthaks.com/604914/factorize-p-3-27?show=604916#a604916
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