Factorize the expression x(x - 2) (x – 4) + 4x - 8
Answers
Answered by
10
Answer:
hope this helps u....
Step-by-step explanation:
X(x-2) (x-4)+4x-8 = x(x-2) (x-4)+4(x-2)
X(x-2) (x-4)+4x-8 = x(x-2) (x-4)+4(x-2)= (x-2) (x(x-4)+4)
X(x-2) (x-4)+4x-8 = x(x-2) (x-4)+4(x-2)= (x-2) (x(x-4)+4)= (x-2) (x2 - 4x + 4)
X(x-2) (x-4)+4x-8 = x(x-2) (x-4)+4(x-2)= (x-2) (x(x-4)+4)= (x-2) (x2 - 4x + 4)= (x-2) (x-2)2
X(x-2) (x-4)+4x-8 = x(x-2) (x-4)+4(x-2)= (x-2) (x(x-4)+4)= (x-2) (x2 - 4x + 4)= (x-2) (x-2)2= (x-2)3
Answered by
0
Answer:
(x-2) (x-2) (x+1) OR (x-2)² (x+1)
Step-by-step explanation:
x(x-2)(x-4) + 4x-8
x(x-2)(x-4) + 4(x-2)
Now take (x-2) common,
(x-2) {x(x-4) + 4}
(x-2) (x²-4x+4)
Now solve the quadratic eq.
(x-2) {(x²-2x) + (x-2)}
(x-2) {x(x-2) + 1(x-2)}
(x-2) (x-2) (x+1) OR (x-2)² (x+1)
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