Question

factorize the folloeing expressions using suitable agebraic identity
${x}^{2} + 2x + 1$
​

Answer 1

Answer:

(x + 1) (x + 1)

Step-by-step explanation:

Identity used here – (a+b)² = a²+2ab+b²

x² + 2x + 1

= (x)² + 2(x)(1) + (1)²

= (x + 1)²

= (x + 1) (x + 1)

Answer 2

Answer:

$\tt {x}^{2} + 2x + 1 \\ \tt= {x}^{2} + 2 \times x \times 1 + {1}^{2} \\ \tt = {(x + 1)}^{2} \\\tt = (x + 1)(x + 1)$