factorize the following: 2(a+1)^2+3(a+1)-35
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2(a+1)²+3(a+1)-35
We will solve (a+1)² by (a+b)²=a²+b²+2ab identity.
2(a²+1+2a)+3a+3-35
2a²+2+4a+3a+3-35
2a+7a-30
Now slove this equation by splitting the middle term.
2a²-12a+5a-30
2a(a-6)+5(a-6)
(2a+5) (a-6) is the final answer of this question..
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