Question

factorize the following
3a(p-2q)-b(p-2q)​

Answer 1

3a(p-2q)-b(p-2q)

Take (p-2q) as common

=(p-2q) (3a-b)

Therefore, the answer will be (p-2q) (3a-b).

Answer 2

Answer:

$\huge{\mathcal{\purple{A}\green{N}\pink{S}\blue{W}\purple{E}\green{R}\pink{!}}}$

Given -

• Factorisation 3a( p-2q)-b ( p- 2q)

To find -

• Factorise

Solution -

3a ( p- 2q )- b( p- 2q)

(-3ab )( p- 2q)

[-3ab] [ p- 2q]

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