Question

factorize the following-
3x+27x²-9

Answer 1

Answer:

(x-3)^3 x^3-9x^2+27x-27 =x^3-27-9x ^2+27x =(x-3)(x^2+3x+9)-9x(x-3) =(x-3)*(x^2+3x+9-9x) =(x-3)*(x^2-6x+9) =(x-3)*(x-3)^2 =(x-3)^3.