Question

factorize the following 64-x^2​

Answer 1

Answer:

(8-x)(8+x)

Step-by-step explanation:

64 - x ^ 2

= (8 ^ 2 - x ^ 2)

= (8 - x)(8 + x)               <As a^2 - b^2 = (a-b)(a+b)>

Answer 2

Answer:

$\Large\boxed{-(x+8)(x-8)}$

Step-by-step explanation:

Given:

To find the factors of 64-x², first you have to isolate it on one side of the equation.

Solutions:

Used distributive property.

$\Large\boxed{\textnormal{DISTRIBUTIVE PROPERTY}}$

$\displaystyle a(b+c)=ab+ac$

First, common term of -1.

$\displaystyle -(x^2-64)$

Solve.

$\Large\boxed{\textnormal{TWO SQUARES FORMULA}}$

$\displaystyle X^2-Y^2=(X+Y)(X-Y)$

$\displaystyle X^2-8^2=\boxed{(X+8)(X-8)}$

$\Large\boxed{-(x+8)(x-8)}$

Therefore, the final answer is -(x+8)(x-8).