Question

Factorize the following
8x2-18x+9

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Answer 1

Answer:

$\large \underline \mathfrak \red{Question}$

Factorise the following 8x²-18x+9

$\large \underline \green{ \rm \: Steps \: required \: to \: factorize}$

→ Find two numbers that multiply to give ac (in other words a times c), and add to give b.

→ Rewrite the middle with those numbers:

→ Factor the first two and last two terms separately:

→ If we've done this correctly, our two new terms should have a clearly visible common factor.

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→→ NOW FACTORISE ACCORDING TO THE GIVEN STEPS ABOVE ↑↑

$\sf{ {8x}^{2} - 18x + 9}$

$\sf{ {8x}^{2} - 12x - 6x + 9}$

$\sf{4x(2x - 3) - 3(2 x - 3)}$

$\sf{(4x - 3)(2x - 3)}$

The factors are ( 4x - 3 ) and ( 2x - 3 )

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$\rm \blue{@BrainlyBlockBusterBB}$

Answer 2

Answer:

8x

2

−18x+9=8x

2

−12x−6x+9=4x(2x−3)−3(2x−3)=(2x−3)(4x−3)