Factorize the following 9c²-22c +8
Answers
Answer:
okkkkkkkkkkkkkkkkkkk wait
Answer:
9x
2
−22x+8=(x−2)(9x−4)
Step-by-step explanation:
Given : Expression 9x^2-22x+89x
2
−22x+8
To find : Factorise the given expression?
Solution :
The solution of a quadratic equation ax^2+bx+c=0ax
2
+bx+c=0 is
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}x=
2a
−b±
b
2
−4ac
On comparing with 9x^2-22x+8=09x
2
−22x+8=0
a=9 , b=-22, c=8
Substitute the values in the solution,
x=\frac{-(-22)\pm\sqrt{(-22)^2-4(9)(8)}}{2(9)}x=
2(9)
−(−22)±
(−22)
2
−4(9)(8)
x=\frac{22\pm\sqrt{484-288}}{18}x=
18
22±
484−288
x=\frac{22\pm\sqrt{196}}{18}x=
18
22±
196
x=\frac{22\pm 14}{18}x=
18
22±14
x=\frac{11\pm 7}{9}x=
9
11±7
x=\frac{11+7}{9},\frac{11-7}{9}x=
9
11+7
,
9
11−7
x=\frac{18}{9},\frac{4}{9}x=
9
18
,
9
4
x=2,0.44x=2,0.44
Therefore, The value of x is 2,0.44.
Factorise form is 9x^2-22x+8=(x-2)(9x-4)9x
2
−22x+8=(x−2)(9x−4)
Step-by-step explanation:
hope it is helpful for you and please mark me brainiest please follow and give lots of thanks also