Question

factorize the following a^2-1-2b-b^2
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Answer 1

Answer:

a^2−b^2−2b−1 is the answer

Step by step :-

a^2-1-2b-b^2

= a^2−b^2−2b

Answer 2

Answer:

The factors of equation $a^{2} -1-2b-b^{2}$ is $-b(a^{2} -1)(2+b)$.

Step-by-step explanation:

Given : The equation is $a^{2} -1-2b-b^{2}$.

To find : The factors of this equation.

Solution :

• The given equation is $a^{2} -1-2b-b^{2}$.
• We have to find the factors of this equation.
• To find the factors, we have to take common terms out from the two groups of two terms each.
• So, the equation is,  

   $a^{2} -1-2b-b^{2}$ = $(a^{2} -1)-(2b-b^{2})$

                        = $(a^{2} -1)-b(2+b)$

                        = $-b(a^{2} -1)(2+b)$

• ∴ The factors of equation $a^{2} -1-2b-b^{2}$ is $-b(a^{2} -1)(2+b)$.