Question

factorize the following
a) x^2+4y^2+4+4x-4xy-8y
b)64a^3+125b^3+240a^2b+300ab^2​

Answer 1

Step-by-step explanation:

b)64a^3+125b^3+240a^2b+300ab^2

= (4a)³+(5b)³+3(4a)²(5b)+3(4a)(5b)²

= (4a)³+(5b)³+3(4a)(5b)(4a+5b)

it gives the think of identity

(a+b)³= a³+b³+3ab(a+b)

(4a)³+(5b)³+3(4a)(5b)(4a+5b) = (4a+5b)³

factorise form will be..

(4a+5b)(4a+5b)(4a+5b)

I hope it helps you!!