factorize the following algebraic expressions by splitting the middle term 40+3p-(p) 2
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40 + 3p - p^2
= - 1 [ p^2 - 3p - 40]
= - 1 [ p^2 - 8p + 5p - 40]
= - 1 [ p( p - 8) + 5(p-8)]
= - 1 (p-8) (p +5)
= (8 - p) (p+ 5)
= - 1 [ p^2 - 3p - 40]
= - 1 [ p^2 - 8p + 5p - 40]
= - 1 [ p( p - 8) + 5(p-8)]
= - 1 (p-8) (p +5)
= (8 - p) (p+ 5)
Answered by
3
40 + 3p - p^2
= - 1 [ p^2 - 3p - 40]
= - 1 [ p^2 - 8p + 5p - 40]
= - 1 [ p( p - 8) + 5(p-8)]
= - 1 (p-8) (p +5)
= (8 - p) (p+ 5)
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