Question

Factorize the following by splitting the middle term:

(a) 3x2 + 11x+30
(b) x2-13x+40​

Answer 1

Step-by-step explanation:

$\bold \color{red}{ {3x}^{2} + 11x + 30}$

$\rightarrow \bold{solution : }$

$\bold{ = {3x}^{2} + (6 + 5)x + 30}$

$= \bold{3x(x + 2) + 5(x + 6)}$

$\bold{ = 3x(x + 2) + 5(x + 2)}$

$\bold{ = (x + 2)(3x + 5)}$

$\bold \color{blue}{ {x}^{2} - 13x + 40 }$

$\rightarrow \bold{solution : }$

$= \bold{ {x}^{2} - 13x + 40 }$

$= \bold{ {x}^{2} + ( - 8 - 5)x + ( - 8)( - 5) }$

$\bold{ = ( {x} - 8)(x - 5)}$