Factorize the following by using a suitable identity.
(a) x⁵-x
(b) x⁶-y⁶
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Step-by-step explanation:
(a) x⁵-x = x (x^4 - 1) = x(x^2+1)(x^2-1) = x (x^2+1)(x+1)(x-1) [by a^2-b^2= (a+b)(a-b)]
(b) x⁶-y⁶ = (x^3+y^3)(x^3-y^3) = (x^3+y^3)(x-y)(x^2+y^2+xy) [by by a^2-b^2= (a+b)(a-b) & a^3-b^3= (a-b)(a^2+b^2+ab)]
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