Math, asked by pavithrab2402, 7 months ago

factorize the following equation 27a³b³+8

Answers

Answered by twiinkle

1

Answer:

(3ab+2)(9a²b²-6ab+4)

Step-by-step explanation:

27a³b³+8

=(3ab)³ + 2³

a³ + b³ = (a+b)(a²-ab+b²)

(3ab)³+2³=(3ab+2)[(3ab)²-3ab×2+2²]

=(3ab+2)(9a²b²-6ab+4)

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