factorize the following equation 27a³b³+8
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Answer:
(3ab+2)(9a²b²-6ab+4)
Step-by-step explanation:
27a³b³+8
=(3ab)³ + 2³
a³ + b³ = (a+b)(a²-ab+b²)
(3ab)³+2³=(3ab+2)[(3ab)²-3ab×2+2²]
=(3ab+2)(9a²b²-6ab+4)
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