Factorize the following expression: x^3 y/9 - x y^3/ 16
Answers
Answer:
STEP
1
:
Equation at the end of step 1
((x3) • y) - 32xy3
STEP
2
:
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
x3y - 9xy3 = xy • (x2 - 9y2)
Trying to factor as a Difference of Squares:
3.2 Factoring: x2 - 9y2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 9 is the square of 3
Check : x2 is the square of x1
Check : y2 is the square of y1
Factorization is : (x + 3y) • (x - 3y)
Final result :
xy • (x + 3y) • (x - 3y)
Terms and topics
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Canceling out