Math, asked by mahapatraashok, 10 months ago

Factorize the following expressions
1. 8x^2-18x+9

Answers

Answered by heeraskaushik
1

Step-by-step explanation:

The first term is, 8x2 its coefficient is 8 .

The middle term is, +18x its coefficient is 18 .

The last term, "the constant", is +9

Step-1 : Multiply the coefficient of the first term by the constant 8 • 9 = 72

Step-2 : Find two factors of 72 whose sum equals the coefficient of the middle term, which is 18 .

-72 + -1 = -73

-36 + -2 = -38

-24 + -3 = -27

-18 + -4 = -22

-12 + -6 = -18

-9 + -8 = -17

-8 + -9 = -17

-6 + -12 = -18

-4 + -18 = -22

-3 + -24 = -27

-2 + -36 = -38

-1 + -72 = -73

1 + 72 = 73

2 + 36 = 38

3 + 24 = 27

4 + 18 = 22

6 + 12 = 18 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 6 and 12

8x2 + 6x + 12x + 9

Step-4 : Add up the first 2 terms, pulling out like factors :

2x • (4x+3)

Add up the last 2 terms, pulling out common factors :

3 • (4x+3)

Step-5 : Add up the four terms of step 4 :

(2x+3) • (4x+3)

Which is the desired factorization

Final result :

(-4x - 3) • (2x + 3)

Answered by shreyasharyan03
1

Step-by-step explanation:

8x² - 18x + 9

18 ± √(18)² - 4*(8)*(9)/16

18 ± √324 - 288/16

18 ± √36/16

18 ± 6/16

Zeroes-

18 + 6/16

24/16 = 3/2

And

18 - 6/16

12/16 = 3/4

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