factorize the following expressions;
i) 5x^2-20xy
ii)5a(b+c)-7b (b+c)
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Answers
Answered by
19
Hi dear
1)5x^2-20xy
take common 5x
we
get
5x(x-4y)
2)5a(b+c)-7b(b+c)
take( b+c) common
we get
(b+c)(5a-7b)
these are the factor
hope it help u
1)5x^2-20xy
take common 5x
we
get
5x(x-4y)
2)5a(b+c)-7b(b+c)
take( b+c) common
we get
(b+c)(5a-7b)
these are the factor
hope it help u
Nightmare1069:
hahhahah
Answered by
18
★ REDUCTION TO FACTORS ★
☣) 5x² - 20xy = 5x [ x - 4y ]
☣) 5a(b + c) - 7b ( b+ c) =
5ab + 5ac - 7b² - 7bc =
5ab - 7b² + 5ac - 7bc =
b ( 5a - 7b ) + c ( 5a - 7b ) =
( b + c) [ 5a - 7b ]
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
☣) 5x² - 20xy = 5x [ x - 4y ]
☣) 5a(b + c) - 7b ( b+ c) =
5ab + 5ac - 7b² - 7bc =
5ab - 7b² + 5ac - 7bc =
b ( 5a - 7b ) + c ( 5a - 7b ) =
( b + c) [ 5a - 7b ]
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
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