factorize the following polynomial.4x^3-7x+3 i want full answer
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Solution:
4x^2-7x+3 = 0
4x^2-3x-4x+3 = 0
x(4x-3) -1(4x-3) = 0
(4x-3) (x-1) = 0
x = 3/4 and x = 1
Thanks for asking
4x^2-7x+3 = 0
4x^2-3x-4x+3 = 0
x(4x-3) -1(4x-3) = 0
(4x-3) (x-1) = 0
x = 3/4 and x = 1
Thanks for asking
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the factors must be
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