Question

Factorize the following polynomials.
(i) (x2 – x)2 –8 (x2 – x) + 12
those who know only answer ​

Answer 1

(x2 - x)2-8(x2 - x)+12

=4x-2x-16x-8x+12

=4x-26x+12

=-22x+12

=12-22x

Answer 2

Answer:

x

2

−x)

2

−8(x

2

−x)+12

y=(x

2

−x)

Then the polynomial becomes,

y

2

−8y+12

=y

2

−6y−2y+12

=y(y−6)−2(y−6)

=(y−2)(y−6)

=(x

2

−x−2)(x

2

−x−6)

Now both factors can be further factorized,

(x ^2−2x+x−2)(x^2)

−3x+2x−6)

={x(x−2)+1(x−2)}{x(x−3)+2(x−3)}

=(x+1)(x−2)(x+2)(x−3