Question

factorize the following polynomials=(x+4)(x-2)²(x-8)-37​

Answer 1

Answer:

Hey!!....Here is ur answer

(x^2-x)^2-8 (x^2-x)+12

Let x^2-x=y

then,

y^2-8y+12

=> y^2-6y-2y+12

=> y (y-6)-2 (y-6)

=> (y-6)(y-2)

Putting the value of y

=> (x^2-x-6)(x^2-x-2)

=> (x^2-3x+2x-6)(x^2-2x+x-2)

=> [x (x-3)+2 (x-3)][x (x-2)+1 (x-2)]

=> (x-3)(x+2)(x-2)(x+1)