factorize the following question:
12x^2y=6xy^2
ap^2+bp^2+bq^2+aq^2
x^2+2x-15
its really urgent. please answer in 10-5 minutes :( i ill mark you as brillianist :D
Answers
Answer:
Step by Step Solution:
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STEP
1
:
Equation at the end of step 1
(((23•3x2) • y) - 6xy) - 45y
STEP
2
:
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
24x2y - 6xy - 45y = 3y • (8x2 - 2x - 15)
Trying to factor by splitting the middle term
3.2 Factoring 8x2 - 2x - 15
The first term is, 8x2 its coefficient is 8 .
The middle term is, -2x its coefficient is -2 .
The last term, "the constant", is -15
Step-1 : Multiply the coefficient of the first term by the constant 8 • -15 = -120
Step-2 : Find two factors of -120 whose sum equals the coefficient of the middle term, which is -2 .
-120 + 1 = -119
-60 + 2 = -58
-40 + 3 = -37
-30 + 4 = -26
-24 + 5 = -19
-20 + 6 = -14
-15 + 8 = -7
-12 + 10 = -2 That's it