Question

Factorize the given polynomial 27y3

+64z

3​

Answer 1

Answer:

$= > (3y + 4z)(9y {}^{2} - 12yz + 16z {}^{2} )$

Step-by-step explanation:

$since \: x {}^{3} + y {}^{3} \\ = (x + y)(x {}^{2} - xy + y {}^{2} )$

$therefore \: 27 {y}^{3} + 64 {z}^{3} = \\ (3y + 4z)((3y) {}^{2} - 3y \times 4z+( 4z) {}^{2} )$

$= > (3y + 4z)(9y {}^{2} - 12yz + 16z {}^{2} )$