Question

factorize the question:​

Answer 1

$\frac{x-2}{8}+\frac{y}{4}-\frac{z+1}{12}$

$\frac{3(x-2)+6y-2(z+1)}{24}$

$\frac{3x-6+6y-2z-2}{24}$

$\frac{3x+6y-2z-8}{24}$

Answer 2

the final answer is ,

$\sf \leadsto \: \: \frac{3x + 6y -2z - 8}{24}$