Factorize the x^2-3x-18
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x2+3x−18
We can Split the Middle Term of this expression to factorise it.
In this technique, if we have to factorise an expression like ax2+bx+c, we need to think of 2 numbers such that:
N1⋅N2=a⋅c=1⋅(−18)=−18
and,
N1+N2=b=3
After trying out a few numbers we get N1=6 and N2=−3
6⋅(−3)=−18 and 6+(−3)=3
x2+3x−18=x2+6x−3x−18
x(x+6)−3(x+6)
(x−3)(x+6) is the factorised form.
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Answer:
(x - 6) (x + 3)
Step-by-step explanation:
==: x² - 3x - 18 = 0
==: x² - 6x + 3x - 18 = 0
==: x (x - 6) + 3 (x - 6) = 0
==: (x - 6) (x + 3)
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