Question

factorize the. Zsquare+6z+12​

Answer 1

$\mathfrak{\bf{\underline{\underline{GIVEN \ :-}}}}$

$ㅤㅤㅤㅤㅤㅤ {z}^{2} + 6z + 12 = 0$

$\mathfrak{\bf{\underline{\underline{SOLUTION \ :-}}}}$

$\implies ㅤㅤㅤㅤ {z}^{2} + 6z + 12 = 0$

$ㅤㅤㅤㅤㅤㅤa = 1 \: \: \: \: b = 6 \: \: \: \: \: c = 12$

$ㅤㅤㅤ {b}^{2} - 4ac = {6}^{2} - 4(1)(12)$

$ㅤ \implies \: ㅤㅤㅤㅤ36 - 48 \\\implies \: \:ㅤㅤㅤㅤ - 12$

$\impliesㅤㅤㅤ \frac{ - b \binom{ + }{ - } \sqrt{ {b}^{2} - 4ac } }{{2a } }$

$\implies \: ㅤㅤㅤ\frac{ - 6 \binom{ + }{ - } \sqrt{ - 12} }{2(1)}$

$\implies \:ㅤㅤ \frac{ - 6 \binom{ + }{ - } 2\sqrt{ 3}i }{2} \: \: \: ..... \sqrt{ - 1} = i$

$\implies \: ㅤㅤㅤㅤ- 3 \binom{ + }{ - } \sqrt{3} i$

$\mathfrak{\bf{\underline{\underline{ANSWER \ :-}}}}$

$ㅤㅤ \boxed{ z = - 3 + \sqrt{3} i }\: \: \: \: OR \: \ \: \: \boxed{ z = - 3 - \sqrt{3} i}$

Answer 2

Step-by-step explanation:

-3+√3i and -3-√3i is the right answer

make it as Brainlist answer......have a good day