Question

factorize the6xfour-23xsquare+20​

Answer 1

solution,

6x⁴-23x²+20

=6x⁴-(15+8)x²+20

=6x⁴-15x²-8c²+20

=3x²(2x²-5)-4(2x²-5)

(3x²-4) (2x²-5)

Answer 2

$\huge \colorbox{yellow}{given}$

${6}^{4} - 23 {x}^{2} + 20$

$\huge \bf \colorbox{red}{solution}$

==》Use an AC method: Find apair of factors of AC= 6 . 20 = 120 which differ by B = 23

==》The pair 15, 8works.

==》Use this pair to split the middle term then factor by grouping as follows:

$\bf 6 {x}^{4} - 23 {x}^{2} + 20 \\ \\ \tt \ = 6 {x}^{4} - (15 + 8) {x}^{2} + 20 \\ \\ = 6 {x}^{4} - 15x - 8 {x}^{2} + 20 \\ \\ = 3 {x}^{2}(2 {x}^{2} - 5) - 4(2 {x}^{2} - 5)$

$\bf{ = (3 {x}^{2} - 4)(2 {x}^{2} - 5)}$

$\huge \bf \fcolorbox{red}{re}{be \: brainly}$

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