Math, asked by sonambhandari17, 8 months ago

Factorize then Divide
(y^2-36y+324) ÷ (y-18)​

Answers

Answered by raghuramansbi
4

Answer:

Solution for y^2-36y+324=0 equation:

Simplifying

y2 + -36y + 324 = 0

Reorder the terms:

324 + -36y + y2 = 0

Solving

324 + -36y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.

(18 + -1y)(18 + -1y) = 0

Subproblem 1

Set the factor '(18 + -1y)' equal to zero and attempt to solve:

Simplifying

18 + -1y = 0

Solving

18 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-18' to each side of the equation.

18 + -18 + -1y = 0 + -18

Combine like terms: 18 + -18 = 0

0 + -1y = 0 + -18

-1y = 0 + -18

Combine like terms: 0 + -18 = -18

-1y = -18

Divide each side by '-1'.

y = 18

Simplifying

y = 18

Subproblem 2

Set the factor '(18 + -1y)' equal to zero and attempt to solve:

Simplifying

18 + -1y = 0

Solving

18 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-18' to each side of the equation.

18 + -18 + -1y = 0 + -18

Combine like terms: 18 + -18 = 0

0 + -1y = 0 + -18

-1y = 0 + -18

Combine like terms: 0 + -18 = -18

-1y = -18

Divide each side by '-1'.

y = 18

Simplifying

y = 18

Solution

y = {18, 18}

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