factorize these questions one by one
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ans 1.
25a2 – 4b2 + 28bc – 49c2
= (5a)2 – (4b2 – 28bc + 49c2)
= (5a)2 – {(2b)2 – 2(2b)(7c) + (7c)2}
= (5a)2 – (2b – 7c)2
= (5a – 2b + 7c)(5a + 2b – 7c)
25a2 – 4b2 + 28bc – 49c2
= (5a)2 – (4b2 – 28bc + 49c2)
= (5a)2 – {(2b)2 – 2(2b)(7c) + (7c)2}
= (5a)2 – (2b – 7c)2
= (5a – 2b + 7c)(5a + 2b – 7c)
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