Question

factorize this question.

Answer 1

The solution is...

$6x {}^{2} + 5x - 6$

$= > 6 {x}^{2} + (9 - 4)x - 6$

$= > 6 {x}^{2} + 9x - 4x - 6$

$= > 3x(2x + 3) - 2(2x + 3)$

$= > (3x - 2)(2x + 3)$

Either,

$3x - 2 = 0 \\ i.e. \: \: 3x = 2 \\ i.e. \: \: \: x = \frac{2}{3}$
Or,

$2x + 3 = 0 \\ i.e. \: \: 2x = - 3 \\ i.e. \: \: x = \frac{ - 3}{2}$
Required roots :

$\frac{2}{3} \: \: and \: \: \frac{ - 3}{2}$