Question

Factorize this: x^2 + x^3 - 1/x^3 + 1/x^2​

Answer 1

Answer:

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Accepted

A way to do it is to write (x+2)(x+3)=x2+6x+6−x, (x+1)(x+6)=x2+6x+6+x, so

(x+2)(x+3)(x+1)(x+6)=(x2+6x+6)2−x2

which gives that

(x+2)(x+3)(x+1)(x+6)−3x2=(x2+6x+6)2−4x2=(x2+4x+6)(x2+8x+6).

Hiiii, hope it helps you